On the segment CD there are two points M and N. So point m lies between points C and N.

On the segment CD there are two points M and N. So point m lies between points C and N. Find the length of the segment MN if CD = 33 cm, CH = 20cm, MD = 21 cm.

Let the length of the segment MN be x cm.

1) CM + MN = CN.

CM + x = 20.

CM = 20 – x (cm).

2) MN + ND = MD.

x + ND = 21.

ND = 21 – x (cm).

3) CM + MN + ND = CD.

(20 – x) + x + (21 – x) = 33.

20 – x + x + 21 – x = 33.

20 + 21 – 33 = x.

x = 8 (cm).

Answer: the length of the segment MN is 8 cm.



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