On the small piston of the hydraulic machine, which has an area of 20 cm3, a weight of 1 kg is installed.

On the small piston of the hydraulic machine, which has an area of 20 cm3, a weight of 1 kg is installed. what weight should be installed on a large piston that has an area of 200 cm2 so that the system is in equilibrium.

F1 / F2 = S1 / S2 (hydraulic press)
20 cm ^ 2 = 0.002 m ^ 2-S1
200 cm ^ 2 = 0.02 m ^ 2-S2
F2 = F1 * S2 / S1 (proportion)
F2 = 10 * 0.02 / 0.002
F2 = 100 (n)
F2 = mg
m = F2 / g
m = 100/10 = 10 (kg)