On what area of support should a 20 kg load be placed in order to produce a pressure of 400 kPa?
| August 16, 2021 | education
solution
S = F / P, where F = m * g (m = 20 kg, g = 10 m / s ^ 2), P = 400 kPa.
S = F / P = m * g / P = 20 * 10/400 = 0.5 m ^ 2.
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