One car drove through the tunnel in 40 seconds. at a speed of 20 m / s. And the other, moving evenly
| September 5, 2021 | education
One car drove through the tunnel in 40 seconds. at a speed of 20 m / s. And the other, moving evenly, drove through the tunnel in 50 seconds. What is the speed of the second car?
t1 = 40 s.
V1 = 20 m / s.
t2 = 50 s.
V2 -?
In order to find the speed of the second car V2, it is necessary to divide the length of the tunnel S by the time of its passage t2: V2 = S / t2.
The length of the tunnel S is found by the formula: S = V1 * t1, where V1 is the speed of the first car through the tunnel, t1 is the time the first car passes the tunnel.
The formula for determining the speed of the second car will take the form: V2 = V1 * t1 / t2.
V2 = 20 m / s * 40 s / 50 s = 16 m / s.
Answer: the speed of the second car through the tunnel was V2 = 16 m / s.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
