One car, moving at a speed of 12 m / s for 10 seconds, made the same movement as the other in 15 s

One car, moving at a speed of 12 m / s for 10 seconds, made the same movement as the other in 15 seconds. What is the speed of the second car if both were moving evenly.

Task data: V1 (speed of one car) = 12 m / s; t1 (duration of movement of one car) = 10 s; t2 (duration of movement of another car) = 15 s; uniform movement of cars; the cars made the same movement.

To determine the speed of another car, we use the equation: V1 * t1 = S (displacement) = V2 * t2, whence V2 = V1 * t1 / V2.

Let’s calculate: V2 = 12 * 10/15 = 8 m / s.

Answer: Another car was moving at a speed of 8 m / s.