One car, moving at a speed of 16 m / s, drove through the tunnel in 30 s, and the other, moving evenly, drove through
| July 3, 2021 | education
One car, moving at a speed of 16 m / s, drove through the tunnel in 30 s, and the other, moving evenly, drove through the same tunnel in 24 s. What is the speed of the second car?
Initial data: V1 (speed of the first car) = 16 m / s; t1 (duration of the passage of the tunnel by the first car) = 30 s; t2 (time of movement through the tunnel of the second car) = 24 s.
The speed of the second car is determined from the equality: V1 * t1 = S (tunnel length) = V2 * t2, whence V2 = V1 * t1 / t2.
Calculation: V2 = 16 * 30/24 = 20 m / s.
Answer: The second car was moving through the tunnel at a speed of 20 m / s.
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