One car moving evenly at a speed of 72 km / h for 10 seconds covered the same path
| February 16, 2021 | education
One car moving evenly at a speed of 72 km / h for 10 seconds covered the same path, another car covered the same speed in 12.5 seconds. What is the speed of the second car.
Task data: V1 (constant speed of the first car) = 72 km / h (20 m / s); t1 (duration of movement of the first car) = 10 s; t2 (duration of movement of the second car) = 12.5 s; cars have traveled the same path S = S1 = S2.
The speed of the second car is determined from the equality: V1 * t1 = S = V2 * t2, whence V2 = V1 * t1 / t2.
Calculation: V2 = 20 * 10 / 12.5 = 16 m / s.
Answer: The speed of the second car was 16 m / s.
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