One charge of 3 * 10 ^ -8 and the second charge of -5 * 10 ^ -8 are 6 cm apart.

One charge of 3 * 10 ^ -8 and the second charge of -5 * 10 ^ -8 are 6 cm apart. Find the Sioux of the interaction between them.

Data: q1 (module of the first charge) = 3 * 10 ^ -8 C; q2 (module of the second charge) = 5 * 10 ^ -8 C; R (distance at which the two charges under consideration are located) = 6 cm (0.06 m).

Constants: k (coefficient of proportionality, we assume that the charges are located in the air) = 9 * 10 ^ 9 N * m2 / Cl2.

The force of interaction between charges is determined using the Coulomb law: F = k * q1 * q2 / R ^ 2.

Calculation: F = 9 * 10 ^ 9 * 3 * 10 ^ -8 * 5 * 10 ^ -8 / 0.06 ^ 2 = 0.00375 N (3.75 mN).

Answer: The force of interaction is 3.75 mN.



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