It is known from the condition that one corner of the parallelogram is 2 times larger than the other. In order to find the smaller angle of the parallelogram, we must remember the properties of the angles of the parallelogram and what is the sum of the angles of the quadrilateral.
So, in a parallelogram, opposite angles are equal to each other.
So, we denote one pair of angles using the variable x, then the second pair of angles is equal to 2x.
The angles of a quadrilateral add up to 360 °.
x + x + 2x + 2x = 360;
6x = 360;
x = 360: 6;
x = 60 ° smaller parallelogram angle,
Then the larger one is 60 * 2 = 120 °.
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