One corner of a triangle is 18 degrees less than each of the other two. Find the corners of the triangle.

Let this angle be x degrees, then both other angles are x + 18.

By the theorem of the sum of the angles of a triangle, in any triangle the sum of all its angles is equal to 180.

Let’s compose the equality:

x + (x + 18) + (x + 18) = 180;

3 * x + 36 = 180;

3x = 180 – 36;

3x = 144;

x = 144: 3;

x = 48 – one corner of the triangle;

x + 18 = 48 + 18 = 66 – the other two corners of the triangle.

Answer: 48, 66 and 66.