One corner of the triangle is 2 times less than the other and 28 degrees less than the third. Find all the corners of the triangle.

1. Let’s denote the angles of the triangle by A, B and C.

2. From the conditions of the problem, we compose the following equalities:

A + B + C = 180 degrees (the sum of the angles of a triangle is always 180 degrees);
2 * A = B (one angle is half the size of the other);
A + 28 deg = C.

3. Substitute the second and third equalities in the first. We get: 4 * A = 152 degrees.
That is, A = 38 deg.

4. From the second equality B = 2 * A = 76 deg.

5. From the third equality C = A + 28 deg = 66 deg.

Answer: The angles of the triangle are 38 degrees, 76 degrees and 66 degrees.