One corner of the triangle is 20 ° less than the second and 40 ° less than the third. Find the corners of the triangle.

Let x ° be one angle of a given triangle, then the second angle of the triangle is (x + 20) °, and the third is (x + 40) °.

It is known that the sum of the angles of a triangle is 180 °, which means that you can write the following equality: x + x + 20 + x + 40 = 180.

We solve the composed equation:

x + x + 20 + x + 40 = 180,

3x + 60 = 180,

3x = 180 – 60,

3x = 120,

x = 120: 3,

x = 40.

Therefore, the first angle of the given triangle is 40 °, then the second angle is x + 20 = 40 + 20 = 60 °, and the third is x + 40 = 40 + 40 = 80 °.

Answer: 40 °, 60 ° and 80 °.