One corner of the triangle is 3 more than the other and 30 ° more than the third angle. Find the corners of the triangle.
October 10, 2021 | education
| From the condition it is known that one corner of the triangle is 3 more than the other and 30 ° more than the third angle. In order to find all the angles of a triangle, we will compose and solve an equation.
For this we apply the theorem on the sum of the angles of a triangle. Which says that the sum of the angles of a triangle is 180 °.
Let’s denote one of the angles as x °, then 3x ° the second angle and the third angle we will write as (x + 30) °.
We get the equation:
x + 3x + (x + 30) = 180;
x + 3x + x + 30 = 180;
5x = 180 – 30;
5x = 150;
x = 30 ° smaller angle, 3 * 30 = 90 °, 30 + 30 = 60 °.
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