One corner of the triangle is 3 times the other, and the outside angle of the third corner is 28 degrees. Find the corners of the triangle.

1) Find the third corner.
It is equal to 180-28 = 152º (by the property of the outer corner)
2) Then the sum of the remaining two angles will be equal to 180-152 = 28º
3) Let the angle be the first angle = x, then the second = 3x
x + 3x = 28
x = 7
First angle = 7º, second = 21 °, third = 152º



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