One corner of the triangle is 30 degrees larger than the other and 30 degrees smaller than the third triangle.

One corner of the triangle is 30 degrees larger than the other and 30 degrees smaller than the third triangle. Find all the corners of this triangle.

Let us express the first angle of the triangle in terms of x and compose equations based on the property of triangles, which states that the sum of all angles in any triangle is 180 °:

x is the first corner;

(x + 30) – second angle;

((x + 30) – 30) – third corner;

x + (x + 30) + ((x + 30) -30) = 180;

x + x + 30 + x = 180;

3x + 30 = 180;

3x = 180 – 30;

3x = 150;

x = 150/3;

x = 50 ° – the first angle;

(x + 30) = 50 + 30 = 80 ° – second angle;

((x + 30) – 30) = 50 ° – third angle.