One corner of the triangle is 40 degrees smaller than the other, and 10 degrees larger than the third. Find the corners of the triangle.

From the condition, we know that one of the angles of the triangle is 40 ° less than the other and 10 ° more than the third. In order to find all the angles of a triangle, let’s recall the theorem on the sum of the angles of a triangle.
The angles of a triangle add up to 180 °.
Let’s denote by the variable x the degree measure of one of the angles of the triangle, then the other two angles can be written as (x – 40) ° and (x + 10) °.
Let’s compose and solve the equation:
x + x – 40 + x + 10 = 180;
3x = 180 + 40 – 10;
3x = 210;
x = 210: 3;
x = 70 °.
One 70 ° angle; the second 70 ° – 40 ° = 30 °; the third is 70 ° + 10 ° = 80 °.