One corner of the triangle is 45 ° greater than the second, and the third is 15 ° less than the second

One corner of the triangle is 45 ° greater than the second, and the third is 15 ° less than the second angle. Find the angles of the triangle

From the condition, we know that one corner of the triangle is 45 ° more than the second, and the third is 15 ° less than the second angle. In order to find the angles of a triangle, let’s create and solve a linear equation.

Let us denote by the variable x the degree measure of the second angle. Then the first can be written as (x + 45), and the third can be written as (x – 15).

The angles of a triangle add up to 180 °.

x + x + 45 + x – 15 = 180;

3x + 30 = 180;

We transfer the terms without variable to the right side of the equation.

3x = 180 – 30;

3x = 150;

x = 50 ° second angle, first 50 + 45 = 95 °, and third 50 – 15 = 35 °.