One cyclist for 12 s moved at a speed of 6 m / s, and the second traveled the same section of the path in 9 s.
| March 8, 2021 | education
One cyclist for 12 s moved at a speed of 6 m / s, and the second traveled the same section of the path in 9 s. How fast is the second cyclist on this section of the track?
1) Calculate the distance traveled by the first cyclist.
S1 = V1 * t1, where V1 is the speed of the first cyclist (V1 = 6 m / s), t1 is the movement time of the first cyclist (t1 = 12 s).
S1 = V1 * t1 = 6 * 12 = 72 m.
2) Let’s calculate the speed of the second cyclist, taking into account that he passed the same section of the path.
S2 = S1 = V2 * t2, where t2 is the movement time of the second cyclist (t2 = 9 s).
V2 = S1 / t2 = 72/9 = 8 m / s.
Answer: The speed of the second cyclist is 8 m / s.
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