One cyclist left the city at 10 o’clock in the morning, the second cyclist left the city in the same direction at 13 o’clock
One cyclist left the city at 10 o’clock in the morning, the second cyclist left the city in the same direction at 13 o’clock, after what time will the second cyclist catch up with the first if the first one drives at a speed of 12 km / h and the second at a speed of 15 km / h?
In the first step, you need to find how many kilometers the first cyclist traveled while the second did not move (that is, in 3 hours):
1) 12 * 3 = 36 (km) – the first cyclist passed.
In the second step, you need to find out what the speed of convergence of two cyclists is equal to:
2) 15 – 12 = 3 (km / h) – the speed of convergence of two cyclists.
In the third step, you need to find out how long it will take for the second cyclist to catch up with the first:
3) 36: 3 = 12 (h) – the second cyclist will catch up with the first.
Answer: in 12 hours.