One cyclist moved at a speed of 18 km / h for 12 seconds, and the second cyclist traveled the same path in 9
| May 4, 2021 | education
One cyclist moved at a speed of 18 km / h for 12 seconds, and the second cyclist traveled the same path in 9 seconds. What is the speed of the second cyclist.
Task data: t1 (duration of movement of the first cyclist) = 12 s; V1 (speed of the first cyclist) = 18 km / h (5 m / s); t2 (duration of movement of the second cyclist) = 9 s; cyclists have traveled the same path.
The speed of the second cyclist can be expressed from the equality: V1 * t1 = V2 * t2 = S, whence V2 = V1 * t1 / t2.
Calculation: V2 = 5 * 12/9 = 6.67 m / s (24 km / h).
Answer: The second cyclist must move at a speed of 24 km / h (6.67 m / s).
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