One cyclist moved at a speed of 6 m / s for 10 seconds, and the second traveled the same section of the path in 8 seconds.

One cyclist moved at a speed of 6 m / s for 10 seconds, and the second traveled the same section of the path in 8 seconds. Find the average speed of the second cyclist.

Given:
t1 = 10 s
t2 = 8 s
V1 = 6 m / s
S1 = S2
V2 =?
Decision:
1)
S2 = V2 * t2
V2 = S2 / t2
2)
S1 = V1 * t1
S1 = S2
S2 = V1 * t1
3)
V2 = V1 * t1 / t2
V2 = 10 * 6/8 = 7.5 m / s
Answer: 7.5 m / s