One cyclist moved at a speed of 6 m / s for 12 minutes, and the second traveled the same section
August 19, 2021 | education
| One cyclist moved at a speed of 6 m / s for 12 minutes, and the second traveled the same section of the path in 9 minutes. What is the speed of the second cyclist on this section of the track?
t1 = 12 min = 720 s.
V1 = 6 m / s.
t2 = 9 min = 540 s.
V2 -?
S = V1 * t1.
S = V2 * t2.
V1 * t1 = V2 * t2.
V2 = V1 * t1 / t2.
V2 = 6 m / s * 720 s / 540 s = 8 m / s.
Answer: the speed of the second cyclist is V2 = 8 m / s.
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