One cyclist moved at a speed of 6 m / s for 12 s, and the second traveled the same path in 9 s. What was the speed of the second cyclist?

Let two cyclists move along the same route with the length S₁ = S₂ = S. The first cyclist for t = 12 seconds moved uniformly along this path at a speed v₁ = 6 m / s.
To find the distance traveled by him, use the formula:
S₁ = v₁ ∙ t₁;
S₁ = 6 m / s ∙ 12 s;
S₁ = 72 m.
It is known from the problem statement that the second cyclist traveled the same path in t₂ = 9 seconds. So the speed of the second cyclist is:
v₂ = S₂: t₂ or v₂ = S: t₂
v₂ = 72 m: 9 s
v₂ = 8 m / s.
Answer: 8 m / s is the speed of the second cyclist.