One cyclist moved at a speed of 6 m / s for 12 seconds, and the second traveled the same path in 9 s

One cyclist moved at a speed of 6 m / s for 12 seconds, and the second traveled the same path in 9 seconds. What was the speed of the 2nd cyclist?

Initial data: t1 (duration of movement of the first cyclist) = 12 m / s; V1 (speed of the first cyclist) = 6 m / s; t2 (duration of movement of the second cyclist) = 9 s.
Since these cyclists traveled the same distance, we express the speed of the second cyclist from the equality: V1 * t1 = S (distance traveled) = V2 * t2 and V2 = V1 * t1 / t2.
Let’s make a calculation: V2 = 6 * 12/9 = 8 m / s.
Answer: The second cyclist had to move at a speed of 8 m / s.