One dragonfly flies at a speed of 12 m / s and catches up with a friend who flies at a speed of 10 m / s.

One dragonfly flies at a speed of 12 m / s and catches up with a friend who flies at a speed of 10 m / s. At first, the distance between them was 6 m. In how many seconds will the first dragonfly catch up with the second?

Let’s denote by the unknown variable x seconds – it will take the first dragonfly to catch up with the second.

Then 12 meters – the first dragonfly will fly by until the moment of overtaking.

10x meters – the second dragonfly will fly by until the moment of overtaking.

At first, the distance between the dragonflies was 6 meters. Let’s make the equation:

12x – 6 = 10x;

2x = 6;

x = 3 seconds it will take the first dragonfly to catch up with the second.