One mole expands isothermally, while the volume doubled. What was the pressure after expansion

One mole expands isothermally, while the volume doubled. What was the pressure after expansion, if the initial pressure was P0 = 166 kPa.

The isothermal process is described by the Boyle-Mariotte law:
PV = C,
where P is pressure, V is volume, C is constant.
The law can also be written in the form: P₀V₀ = P₁V₁, if the indices 0 and 1 mean the values of quantities in the initial and final states.
Substitute the values, taking into account that V₁ = 2V₀, and P₀ = 166 kPa:
166 kPa * V₁ = P₁ * 2V₁.
Reduce by V₁
166 kPa = 2 * P₁.
P₁ = 83 kPa.
Answer: 83 kPa.