One mole of an ideal gas was heated isobarically by 72 kelvin, giving it 1.6 kJ of heat.

One mole of an ideal gas was heated isobarically by 72 kelvin, giving it 1.6 kJ of heat. Find the perfect work of the gas and its internal energy.

Data: ν (amount of gas substance) = 1 mol; ΔТ (change in the temperature of the ideal gas during isobaric heating) = 72 K; Q (the amount of heat that was imparted to the gas) = 1.6 kJ (1.6 * 10 ^ 3 J).
Constants: R (universal gas constant) = 8.31 J / (mol * K).
1) Perfect gas work: A = ν * R * ΔT = 1 * 8.31 * 72 = 598.32 J.
2) Change in internal energy: ΔU = Q – A = 1.6 * 10 ^ 3 – 598.32 = 1001.68 J.
Answer: The gas did the work 598.32 J, the change in internal energy is 1001.68 J.