One number is 2 times larger than the other. The arithmetic mean of these numbers is 0.9.

One number is 2 times larger than the other. The arithmetic mean of these numbers is 0.9. What is the lesser of these numbers?

Let us denote by a the lesser of the two given numbers.

In the initial data for this task, it is reported that if the smaller of the two given numbers is doubled, then a larger number will be obtained, therefore, a larger number is 2a.

Also in the problem statement it is said that if you add these two numbers and divide the resulting sum by 2, the result will be 0.9, therefore, we can make the following equation:

(a + 2a) / 3 = 0.9,

solving which, we get:

3a / 2 = 0.9;

a / 2 = 0.9 / 3;

a / 2 = 0.3;

a = 2 * 0.3 = 0.6.

Find another number:

2 * a = 2 * 0.6 = 1.2.

Answer: the required numbers are 0.6 and 1.2.