One of the acute angles is 60º. The sum of the smallest angle and the hypotenuse is 1.8 m.

One of the acute angles is 60º. The sum of the smallest angle and the hypotenuse is 1.8 m. What is the length of the hypotenuse?

Let’s denote the value of the hypotenuse through s, the second acute angle is (90º – 60º) = 30º.

And the size of the smaller leg, opposite the angle of 30º, is equal to half of the hypotenuse c: c / 2. Let’s determine the sum of the hypotenuse and this leg:

c + c / 2 = (3/2) * c 1 = 1.8 m. From where we define the hypotenuse with:

s = 1.8 m: 3/2 = 1.2 m.

Answer: The hypotenuse is 1.2 m.