One of the acute corners of a right-angled triangle is 10 ° larger than the other. Find these corners.

It is known from the condition that one of the acute angles of a right-angled triangle is 10 ° larger than the other. In order to find the degree measures of the angles of a triangle, we will compose and solve a linear equation.

Let’s denote by x ° the smaller acute angle of a right-angled triangle, and by (x + 10) ° – the larger acute angle of a right-angled triangle.

We use the theorem on the sum of the angles of a triangle to compose the equation. It says that the sum of the angles of a triangle is 180 °.

90 + x + (x + 10) = 180;

90 + x + x + 10 = 180;

2x = 180 – 100;

2x = 80;

x = 40 ° smaller angle and 40 + 10 = 50 ° smaller angle.