One of the acute corners of a right triangle is 32 degrees smaller than the other. What is the smaller angle of the triangle?

To solve the problem, let’s compose and solve the equation. We apply the theorem on the sum of the angles of a triangle to compose the equation.

We start by considering the condition of the problem. It says that one of the acute corners of a right-angled triangle is 32 ° less than the other.

So, since the triangle is rectangular, one of its corners is 90 °.

Let’s denote by x ° one of the acute angles, then the degree measure of the second is (x – 32) °.

We get the equation:

x + (x – 32) + 90 = 180;

2x = 180 – 90 + 32;

2x = 122;

x = 61 °.

61 – 32 = 29 °.

Answer: 29 ° and 61 °.