One of the acute corners of the rectangle of the triangle is 43 ° smaller than the other. Find these corners.

A triangle is called rectangular if one of its corners is a straight line (equal to 90º).

The sum of all the angles of the triangle is 180º. Since one of the angles (∠С) of this triangle is 90º, and one of the acute angles (∠А) is 43º less than the other acute angle (∠В), then to calculate the magnitude of these angles we will express:

x – acute angle ∠В;

x – 43 – acute angle ∠A;

x + x – 43 + 90 = 180;

x + x = 180 – 90 + 43;

2x = 133;

x = 133/2 = 66.5;

∠В = 66.5º;

∠A = 66.5º – 43º = 23.5º.

Answer: the angle ∠А is equal to 23.5º; the angle ∠В is equal to 66.5º.