What mass of acetaldehyde can be obtained from technical acetylene with a mass of 260 g

What mass of acetaldehyde can be obtained from technical acetylene with a mass of 260 g, if the mass fraction of impurities in it is 10% and the product yield is 90%?

1.Let’s find the mass of pure acetylene without impurities.

100% – 10% = 90%.

260 g – 100%,

x – 90%,

x = (260 g × 90%): 100% = 234 g.

2.Let’s find the amount of acetylene substance.

n = m: M.

M (C2H2) = 26g / mol.

n = 234 g: 26 g / mol = 9 mol.

3. Let’s compose the equation of the reaction, we will find the quantitative ratios of substances.

НС ≡СН + НОН → Н3С – СОН.

1 mole of acetylene accounts for 1 mole of aldehyde. The substances are in quantitative ratios of 1: 1. The amounts of acetylene and aldehyde will be the same.

n (C2H2) = n (H3C – COH) = 9 mol.

4.Let’s find the mass of the aldehyde by the formula:

m = n × M,

M (Н3С – СОН) = 44 g / mol.

m = 44 g / mol × 9 mol = 396 g.

396 g of aldehyde should be obtained according to calculations. But according to the condition of the problem, the yield of aldehyde is 90%.

5.Let’s find the output of the aldehyde according to the problem statement.

396 g – 100%,

x – 90%,

x = (396 g × 90%): 100% = 356.4 g.

Answer: 356.4 g.