One of the angles of the parallelogram is 127 ° find the rest of the angles.

Given:
ABCE – parallelogram,
angle A = 127 degrees.
Find the degree measures of the angles of the parallelogram ABCE: angle B, angle C, angle E -?
Solution:
Consider a parallelogram ABCE. Its opposite angles are equal to each other, then angle A = angle C = 127 degrees, angle B = angle E.
We know that the sum of the degree measures of a parallelogram is 360 degrees. Hence:
angle B = angle E = (360 – 127 – 127): 2;
angle B = angle E = (233 – 127): 2;
angle B = angle E = 106: 2;
angle B = angle E = 53 degrees.
Answer: 53 degrees; 127 degrees; 53 degrees.