One of the angles of the parallelogram is 32 degrees larger than the other. then the greater angle
| September 9, 2021 | education
One of the angles of the parallelogram is 32 degrees larger than the other. then the greater angle of the parallelogram is …
1. The vertices of the parallelogram A, B, C, D. ∠В are more than ∠А by 32 °, therefore, ∠В = А + 32 °.
2. To solve the problem, we will use the parallelogram property that the total value of the angles located on one side (adjacent) is 180 °:
∠В + ∠А = 180 °.
3. Substitute in this expression ∠А + 32 ° instead of ∠В:
∠А + 32 ° + ∠А = 180 °.
2∠A = 148 °.
∠А = 148 °: 2 = 74 °.
∠B = A + 32 ° = 74 ° + 32 ° = 106 °.
Answer: ∠В = 106 ° – larger angle.
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