One of the angles of the parallelogram is 56 degrees larger than the other. Find the larger angle.

Given:
ABCE – parallelogram,
angle A = 56 + angle B.
Find the degree measures of the angles of the parallelogram ABCE: angle A, angle B, angle C, angle E -?
Decision:
Consider a parallelogram ABCE. Its opposite angles are equal to each other, then angle A = angle C, angle B = angle E.
Let the degree measure of angle B be x degrees, then the degree measure of angle A is 56 + x degrees. We know that the sum of the degree measures of a parallelogram is 360 degrees. Let’s make the equation:
x + x + 56 + x + 56 + x = 360;
x + x + x + x + 112 = 360;
x + x + x + x = 360 – 112;
x + x + x + x = 248;
x * (1 + 1 + 1 + 1) = 248;
x * 4 = 248;
x = 248: 4;
x = 62 degrees – the degree measure of the angle B;
62 + 56 = 118 degrees is the degree measure of angle A.
Answer: 118 degrees; 62 degrees; 118 degrees; 62 degrees.