One of the angles of the parallelogram is 62 degrees larger than the other.
| September 29, 2021 | education
One of the angles of the parallelogram is 62 degrees larger than the other. Find the larger of the angles of the parallelogram.
2α + 2β = 360 °,
β = α + 62 °,
2α + 2 (α + 62 °) = 360 °,
2α + 2α + 124 ° = 360 °,
4α = 360 ° – 124 °,
4α = 236 °,
α = 236 ° / 4,
α = 59 °.
Answer: α = 59 °.
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