One of the angles of the triangle is 2 times smaller than the other and 28 ° smaller than the third.

One of the angles of the triangle is 2 times smaller than the other and 28 ° smaller than the third. Find all the corners of the triangle.

Arithmetic way.
By action 180-28, we leveled the 1st corner and the 3rd corner, and the 2nd one is 2 times larger than the first, we get a total of 4 such angles, which means we divide by 4:
(180-28): 4 = 38 -first corner
38 * 2 = 76 – second corner;
38 + 28 = 66 is the third corner.

Algebraic way.
Let’s take one angle as x, then the second angle will be 2x, and the third angle will be x + 28.
Let’s make the equation:
x + 2x + (x + 28) = 180;
4x + 28 = 180;
4x = 152;
x = 38 – first corner;
2x = 38 * 2 = 76 – second corner;
x + 28 = 38 + 28 = 66 – third angle.
Answer: 38, 76, 66 degrees.