One of the corners of an isosceles triangle = 100 percent find the others.

From the condition it is known that one of the angles of an isosceles triangle is 100 °, and we need to find the degree measure of the remaining angles of the triangle.

Let us first of all recall the theorem on the sum of the angles of a triangle. It says that the sum of the angles of a triangle is 180 °.

In an isosceles triangle, the angles at the base are equal to each other.

So, apparently, the angle given to us in the condition is the angle at the apex of the triangle.

Let’s calculate the sum of the angles at the base:

180 ° – 100 ° = 80 °.

We are looking for corners at the base:

80 °: 2 = 40 °.