One of the corners of an isosceles triangle = 68 degrees. find the rest of the corners.

1) There are two possible solutions:

№ 1. In triangle ABC: AB = BC and angle B = 68 °, then angle A = angle C = (180 ° – 68 °): 2 = 112 °: 2 = 56 °.

No. 2. In triangle ABC: AB = BC and angle A = 68 °, then angle C = 68 °, angle B = 180 ° – (68 ° + 68 °) = 180 ° – 136 ° = 44 °.

Answer: 56 °, 68 °, 56 ° or 68 °, 44 °, 68 °.



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