One of the corners of the triangle is 124. find the acute angle that is formed by the bisector of the other

univerkov | May 28, 2021 | education

One of the corners of the triangle is 124. find the acute angle that is formed by the bisector of the other two sides of the triangle.

The sum of the interior angles of a triangle is 180.

Then the sum of the angles (BAC + BCA) = (180 – ABC) = (180 – 124) = 56.

Since the segments SC and AM are the bisectors of the angles, then the angle OAC = BAC / 2, the angle OCA = BCA / 2.

Then (BAC + BCA) / 2 = 56/2 = 28.

Angle AOC = 180 – 28 = 152.

The AOK angle is adjacent to the AOC angle, then the AOK angle = 180 – 152 = 28.

Answer: The acute angle between the diagonals is 28.

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