# One of the corners of the triangle is 4 times smaller than the other and 30 degrees less than the third

**One of the corners of the triangle is 4 times smaller than the other and 30 degrees less than the third find all the corners of the triangle**

Let one angle be equal to X °. Then the second some angle is equal to 4X ° (since it is 4 times more than the first angle). And the third angle is (X + 30) ° (since it is 30 more than the first angle).

The sum of the angles in a triangle is 180 °, by the property of the sum of angles in a triangle.

Let’s compose and solve the equation:

X + 4X + (30 + X) = 180;

X + 4X + 30 + X = 180;

6X + 30 = 180;

6X = 180 – 30;

6X = 150;

X = 150: 6;

X = 25.

The first angle is 25 °.

Then the second angle is:

4 * 25 = 100 °.

And the third corner:

25 ° + 30 ° = 55 °.

Or:

180 ° – (25 ° + 100 °) = 180 ° – 125 ° = 55 °.

Answer: 25 °; 100 °; 55 °.