One of the inner corners of the triangle is 14 degrees larger than the other, and the outer corner

One of the inner corners of the triangle is 14 degrees larger than the other, and the outer corner at the apex of the third corner is 110 degrees. Find the corners of the triangle.

1. Vertices of triangle А, В, С. ∠В are more than ∠А by 14 °. ALL is the outer corner.

2. We calculate the value of the internal angle at the vertex C, taking into account that the total value of this angle and the adjacent external angle is 180 °:

∠С = 180 ° – 110 ° = 70 °.

3. We take the value of A for x (degrees).

Then ∠B = x + 14 (degrees).

4. Let’s compose an equation, taking into account that the total value of the angles of a given triangle is 180 °:

x + x + 14 + 70 = 180 °;

2x = 96;

x = 48.

∠А = 48 °.

∠В = 48 + 14 = 62 °.

Answer: ∠А = 48 °, ∠В = 62 °, ∠С = 70 °.