One of the legs of a right-angled triangle is half the size of the other. Find the second leg if the hypotenuse = √15?

1. A, B, C – the vertices of the triangle. Angle A = 90 degrees. ВС = √15 units of measurement.

2. According to the problem statement, one of the legs is 2 times smaller than the other. Let’s say AC = 2AB.

3. AC² + AB² = BC² (by the Pythagorean theorem).

4. Substitute in this expression 2AB instead of AC:

4AB² + AB² = 15.

5AB² = 15.

AB = √3 units of measurement.

AC = 2√3 units of measurement.

Answer: leg AB = √3 units, leg AC = 2√3 units.