One of the outer corners of an isosceles triangle is 115 degrees. Find the corners of the triangle.

Answer: CAB angle – 65 degrees, ACB angle – 65 degrees, ABC angle – 50 degrees
Decision:
1) by the condition of the problem – an isosceles triangle, therefore the angles at the base are equal.
2) since the outer angle at the base is 115 degrees, the adjacent angle of the triangle is 65 degrees (180 – 115 = 65 degrees)
3) means the second angle at the base is also 65 degrees
4) the sum of the angles of the triangle is 180 degrees. respectively, 180 – 65 – 65 = 50 degrees