One of the outer corners of an isosceles triangle is 116 degrees and 100 degrees.

One of the outer corners of an isosceles triangle is 116 degrees and 100 degrees. Find the angles of the triangle Consider two cases.

It is known from the condition that one of the outer angles of an isosceles triangle is 1) 116 °; 2) 100 °. You need to find the corners of the triangle.

In the first case:

1) If this is an angle at the base, then the inner one adjacent to it is 180 ° – 116 ° = 64 ° and there are two of them at the base. The apex angle is 180 ° – (64 ° + 64 °) = 52 °.

2) If this is the apex angle, then the inner one adjacent to it is 180 ° – 116 ° = 64 °. And the angles at the base are equal to (180 ° – 64 °) / 2 = 58 °.

Similarly with the second case:

1) If this is an angle at the base, then the inner one adjacent to it is 180 ° – 100 ° = 80 ° and there are two of them at the base. The apex angle is 180 ° – (80 ° + 80 °) = 20 °.

2) If this is the apex angle, then the inner one adjacent to it is 180 ° – 100 ° = 80 °. And the angles at the base are equal to (180 ° – 80 °) / 2 = 50 °.



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