One of the outer corners of an isosceles triangle is 130 degrees, find the inner and outer corners of the triangle

1. Suppose that the outer goal at the apex of an isosceles triangle is known. Let’s define its inner corner.

180 – 130 = 50 °.

2. Find the interior angles at the base.

(180 – 50) / 2 = 65 °.

3. Let’s calculate the degree measure of the external.

180 – 65 = 115 °.

Answer: Internal – 50 °, 65 °, 65 °. External – 130 °, 115 °, 115 °.



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