One of the outer corners of the triangle = 150 degrees, and the other = 110 degrees. Find the corners of the triangle.

Given: triangle ABC
Angle A is adjacent to an angle of 150 degrees. Therefore, angle a is 30 °. Angle B adjacent with an angle of 110 ° is equal to 70 °. Since the sum of two adjacent angles is always 180 °. Angle C is equal to (180-100) ° = 80 °



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