One of the outer corners of the triangle is 126 °. Find the corners of the triangle

One of the outer corners of the triangle is 126 °. Find the corners of the triangle that are not adjacent to it, if one of them is 2 times larger.

Let the value of the smaller of the sought angles be equal to the variable a.

Then, in accordance with the condition of our task, the value of the second sought angle can be represented in the form 2a.

Since, according to the condition of our task, we know for sure that the outer angle of the triangle, which is not adjacent to the angles we are looking for, is 126 °, it is possible to write down the equation and find out what the angles we need will equal:

a + 2a = 126;

3a = 126;

a = 42;

2 * 42 = 84.

Answer: The smaller one is 42 °, the larger one is 84 °.