One of the sharp corners of a right-angled triangle is 10 larger than the other. find these corners.

It is known from the condition that one of the acute angles of a right-angled triangle is 10 ° larger than the other. Find the degree measures of the angles.

We apply the theorem on the sum of the angles of a triangle. It says that the sum of the angles of a triangle is 180 °.

We know that in a right-angled triangle one angle of a straight line is 90 °.

Let us denote a smaller acute angle for x ° and a larger acute angle for (x + 10) °.

We get a linear equation:

x + (x + 10) = 90;

x + x + 10 = 90;

2x = 90 – 10;

2x = 80;

x = 40 ° smaller acute angle and 40 + 10 = 50 ° larger acute angle.